Question
Divide $: 9x^3 − 6x^2$ by $3x$
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Answer
$9 x^3-6 x^2 \text { by } 3 x$
$=\frac{9 x^3-6 x^2}{3 x}$
$=\frac{9 x^3}{3 x}-\frac{6 x^2}{3 x}$
$=3 x^{3-1}-2 x^{2-1}$
$=3 x^2-2 x$
$=\frac{9 x^3-6 x^2}{3 x}$
$=\frac{9 x^3}{3 x}-\frac{6 x^2}{3 x}$
$=3 x^{3-1}-2 x^{2-1}$
$=3 x^2-2 x$
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