Question
Divide and write the quotient and the remainder.
$\left(6 x^5-4 x^4+8 x^3+2 x^2\right) \div 2 x^2$
$\left(6 x^5-4 x^4+8 x^3+2 x^2\right) \div 2 x^2$
✓
Answer
$\left(6 x^5-4 x^4+8 x^3+2 x^2\right) \div 2 x^2$
$\therefore$ Quotient $=3 x ^3-2 x ^2+4 x +1$
Remainder $=0$
$\therefore$ Quotient $=3 x ^3-2 x ^2+4 x +1$
Remainder $=0$
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