Question
Divide the given polynomial by the given monomial: $\left(3 y^8-4 y^6+5 y^4\right) \div y^4$
✓
Answer
$\left(3 y^8-4 y^6+5 y^4\right) \div y^4$
$= {3y^8- 4y^6 +5y^4} \over y^4$
$ = \frac{{{y^4}(3{y^4} - 4{y^2} + 5)}}{{{y^4}}}$
$= 3y^4– 4y^2+ 5$
$= {3y^8- 4y^6 +5y^4} \over y^4$
$ = \frac{{{y^4}(3{y^4} - 4{y^2} + 5)}}{{{y^4}}}$
$= 3y^4– 4y^2+ 5$
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