Question
Divide the given polynomial by the given monomial: $\left(x^3+2 x^2+3 x\right) \div 2 x$

Answer

$\left(x^3+2 x^2+3 x\right) \div 2 x$
$ = \frac{{{x^3} + 2{x^2} + 3x}}{{2x}}$
$ = \frac{{x({x^2} + 2x + 3)}}{{2x}}$
$ = x^2 + 2x+ 3 \over 2$

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