Question
Divide the sum $\frac{65}{12}$ and $\frac{8}{3}$ by their difference.
✓
Answer
Sum $=\frac{65}{12}+\frac{8}{3}=\frac{65+32}{12}=\frac{97}{12}$Difference $=\frac{65}{12}-\frac{8}{3}=\frac{65-32}{12}=\frac{33}{12}$
$=\frac{97}{12}\div=\frac{33}{12}$
$=\frac{97}{12}\times=\frac{12}{33}$
$=\frac{97}{33}$
$=\frac{97}{12}\div=\frac{33}{12}$
$=\frac{97}{12}\times=\frac{12}{33}$
$=\frac{97}{33}$
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