Question
Divide $x+2 x^2+3 x^4-x^5$ by $2 x$.
✓
Answer
$\frac{\text{x}+2\text{x}^2+3\text{x}^4-\text{x}^5}{2\text{x}}$
$=\frac{\text{x}}{2\text{x}}+\frac{2\text{x}^2}{2\text{x}}+\frac{3\text{x}^4}{2\text{x}}-\frac{\text{x}^5}{2\text{x}}$
$=\frac{1}{2}+\text{x}+\frac{3}{2}\text{x}^3-\frac{1}{2}\text{x}^4$
$=\frac{\text{x}}{2\text{x}}+\frac{2\text{x}^2}{2\text{x}}+\frac{3\text{x}^4}{2\text{x}}-\frac{\text{x}^5}{2\text{x}}$
$=\frac{1}{2}+\text{x}+\frac{3}{2}\text{x}^3-\frac{1}{2}\text{x}^4$
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