Question
Divide $x^2-5 x+6$ by $(x-3)$

Answer

$\frac{\text{x}^2-5\text{x}+6}{\text{x}-3}$
$=\frac{\text{x}^2-3\text{x}-2\text{x}+6}{\text{x}-3}$
$=\frac{\text{x}^2-3\text{x}-2\text{x}+6}{\text{x}-3}$
$=\frac{\text{x}(\text{x}-3)-2(\text{x}-2)}{\text{x}-3}$
$=\frac{(\text{x}-3)(\text{x}-2)}{\text{x}-3}=\text{x}-2$

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