MCQ
Divide $x(4x^2 - 100)$ by $4x(x + 5)$
- ✓$(x - 5)$
- B$(x^2 - 25)$
- C$(x + 5)$
- D$(x + 5)^2$
✓
Answer
Correct option: A.
$(x - 5)$
A. $(x - 5)$
Solution:
$\frac{\text{x}(4\text{x}^2-100)}{\text{x}(\text{x}-5)}$
$\Rightarrow\frac{\text{x}((2\text{x})^2-(10)^2)}{4\text{x}(\text{x}+5)}$
$\Rightarrow\frac{\text{x}(2\text{x}+10)(\text{2x}-10)}{4\text{x}(\text{x}+5)}$
$\Rightarrow\frac{2\text{x}(\text{x}+5)(2\text{xx}-10)}{2\times2\text{x}(\text{x}+5)}$
Cancel the common factors
$\Rightarrow\frac{2(\text{x}-5)}{2}=(\text{x}-5)$
Solution:
$\frac{\text{x}(4\text{x}^2-100)}{\text{x}(\text{x}-5)}$
$\Rightarrow\frac{\text{x}((2\text{x})^2-(10)^2)}{4\text{x}(\text{x}+5)}$
$\Rightarrow\frac{\text{x}(2\text{x}+10)(\text{2x}-10)}{4\text{x}(\text{x}+5)}$
$\Rightarrow\frac{2\text{x}(\text{x}+5)(2\text{xx}-10)}{2\times2\text{x}(\text{x}+5)}$
Cancel the common factors
$\Rightarrow\frac{2(\text{x}-5)}{2}=(\text{x}-5)$
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