Key concept: In this problem first we have to find the direction of magnetic field due to one wire at the point on other wire, then the magnetic force on that current carrying wire.
According to Biot-Savart's law, magnetic field B is parallel to idl × r and idl is the current carrying element having it's direction along the direction of flow of current.
Here, for the direction of magnetic field, at dl2, located at (0, R, 0) due to wire dlx is given by B || idl × r or i × j (because point (0, R, 0) lies ony-axis), but i × j = k.
So, the direction of magnetic field at dl2 is along z-direction.
The direction of magnetic force exerted at dl2 due to the magnetic field of first wire is along the x-axis.
F - i(l × B), i.e., F || (i × k) or along -j direction.
Therefore, force due to dl [on dl2 is non-zero.]
Now, for the direction of magnetic field, at dx, located at (0, 0, 0) due to wire d2 is given by B || idl × r or j × -j (because origin lies on y-direction w.r.t. point (0, R, 0), but j × -j = 0.
So, the magnetic field at dx does not exist.
Force due to dl2 on dl1, is zero.
So, magnetic forces do not obey Newton's third law. But they obey Newton's third law if current carrying element are placed parallel to each other.