MCQ
$\begin{array}{*{20}{c}}
{2C{H_3} - C = C{H_2}} \\
{\,|} \\
{\,\,\,Ph}
\end{array}\xrightarrow{{H - A\,(acid)}}\mathop {(A)}\limits_{(major)} $
{2C{H_3} - C = C{H_2}} \\
{\,|} \\
{\,\,\,Ph}
\end{array}\xrightarrow{{H - A\,(acid)}}\mathop {(A)}\limits_{(major)} $
Product $(A)$ is
- A
- B
- ✓
- D
