MCQ
$\begin{array}{*{20}{c}}
  {\begin{array}{*{20}{c}}
  {CH = O\,\,\,\,\,\,\,\,\,\,} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} 
\end{array}} \\ 
  {{{(CH - OH)}_4}} \\ 
  {\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {C{H_2} - OH} 
\end{array}$ $\xrightarrow{{B{r_2}/{H_2}O}}P$ ; $P$ is
  • $\begin{array}{*{20}{c}}
      {\begin{array}{*{20}{c}}
      {COOH\,\,\,\,\,\,\,\,\,\,} \\ 
      {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} 
    \end{array}} \\ 
      {{{(CH - OH)}_4}} \\ 
      {\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
      {C{H_2} - OH} 
    \end{array}$
  • B
    $\begin{array}{*{20}{c}}
      {\begin{array}{*{20}{c}}
      {CH = O\,\,\,\,\,\,\,\,\,\,} \\ 
      {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} 
    \end{array}} \\ 
      {{{(CH - OH)}_4}} \\ 
      {\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
      {\,\,COOH\,\,\,\,\,\,\,\,\,\,\,\,} 
    \end{array}$
  • C
    $\begin{array}{*{20}{c}}
      {\begin{array}{*{20}{c}}
      {CH = O\,\,\,\,\,\,\,\,\,\,} \\ 
      {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} 
    \end{array}} \\ 
      {{{(CH - OH)}_4}} \\ 
      {\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
      {\,\,CH = O\,\,\,\,\,\,\,\,\,\,\,\,} 
    \end{array}$
  • D
    $\begin{array}{*{20}{c}}
      {\begin{array}{*{20}{c}}
      {COOH\,\,\,\,\,\,\,\,\,\,} \\ 
      {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} 
    \end{array}} \\ 
      {{{(CH - OH)}_4}} \\ 
      {\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
      {\,\,COOH\,\,\,\,\,\,\,\,\,\,\,\,} 
    \end{array}$

Answer

Correct option: A.
$\begin{array}{*{20}{c}}
  {\begin{array}{*{20}{c}}
  {COOH\,\,\,\,\,\,\,\,\,\,} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} 
\end{array}} \\ 
  {{{(CH - OH)}_4}} \\ 
  {\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {C{H_2} - OH} 
\end{array}$
a

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