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STD 11 - 9. Hydricarbon — NEET STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceNEETSTD 11 - 9. Hydricarbon4 Marks
MCQ
$\begin{array}{*{20}{c}}
  {C{H_2} - C{O_2}K} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {C{H_2} - C{O_2}K} 
\end{array}\xrightarrow{{electrolysis}}\mathop {(A)}\limits_{\left( {major} \right)} $ (Kolbe electrolysis method)

Product $(A)$ of the reaction is 

  • A
    $CH_3 - CH_3$
  • ✓
    $CH_2 = CH_2$
  • C
    $CH_3 -CH = CH_2$
  • D
    none of these
✓

Answer

Correct option: B.
$CH_2 = CH_2$
b

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