Question
$\begin{array}{*{20}{c}}
{C{H_3} - CH = C - C = CH - C{H_3}}\\
{|\,\,\,\,\,\,\,\,\,|}\\
{\,Br\,\,\,\,Cl}
\end{array}$

How many geometrical isomers are possible for this compound?

Answer

c
$(c)$ Total $G.I = 2^2 = 4$

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In the reaction sequence:

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The $IUPAC$ name of $\begin{array}{*{20}{c}}
  {C{H_2} - C = CH - C{H_2}OH} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {\,\,\,\,Cl\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_{3\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} 
\end{array}$ is
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$(III)\,\,\,\begin{matrix}
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   |\,  \\
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   |\,  \\
   \,\,\,C{{H}_{3}}  \\
\end{matrix}$

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