MCQ
$\begin{array}{*{20}{c}}
  {C{H_3} - CH - CH = C{H_2}} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,} 
\end{array}$ $\xrightarrow{{{\text{D}}Br}}\,Product \,\left( {Major} \right)$ Product will be
  • A
    $\begin{array}{*{20}{c}}
      {Br\,\,\,\,\,\,\,\,\,\,\,} \\ 
      {|\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
      {C{H_3} - C - CH - C{H_3}} \\ 
      {\,|\,\,\,\,\,\,\,\,\,|\,\,\,\,\,} \\ 
      {C{H_3}\,D\,\,\,\,} 
    \end{array}$
  • B
    $\begin{array}{*{20}{c}}
      {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Br\,\,\,\,\,\,\,\,D\,} \\ 
      {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,} \\ 
      {C{H_3} - CH - CH - C{H_2}} \\ 
      {\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
      {C{H_3}\,\,\,\,\,\,\,\,\,\,} 
    \end{array}$
  • $\begin{array}{*{20}{c}}
      {Br\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
      {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
      {C{H_3} - C - C{H_2} - C{H_2}D} \\ 
      {\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
      {C{H_3}\,\,\,\,\,\,\,\,\,\,\,} 
    \end{array}$
  • D
    $\begin{array}{*{20}{c}}
      {\,\,Br\,\,\,\,\,\,\,\,\,D\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
      {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
      {C{H_2} - C - C{H_2} - C{H_3}} \\ 
      {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
      {C{H_3}\,\,\,\,\,\,\,\,\,\,} 
    \end{array}$

Answer

Correct option: C.
$\begin{array}{*{20}{c}}
  {Br\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {C{H_3} - C - C{H_2} - C{H_2}D} \\ 
  {\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {C{H_3}\,\,\,\,\,\,\,\,\,\,\,} 
\end{array}$
c

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