$\begin{array}{*{20}{c}}
{C{H_3} - CH - C{H_3}} \\
{|\,\,\,\,\,} \\
{\,\,N{H_2}}
\end{array}$ ${\xrightarrow{{HN{O_2}}}A}$ ${\xrightarrow{{oxidation}}B}$ ${\xrightarrow[{(ii){\kern 1pt} {H_2}O}]{{(i)C{H_3}MgI}}C}$

$C$ is

Q: $\begin{array}{*{20}{c}} {C{H_3} - CH - C{H_3}} \\ {|\,\,\,\,\,} \\ {\,\,N{H_2}} \end{array}$ ${\xrightarrow{{HN{O_2}}}A}$ ${\xrightarrow{{oxidation}}B}$ ${\xrightarrow[{(ii){\kern 1pt} {H_2}O}]{{(i)C{H_3}MgI}}C}$ $C$ is

d $\begin{matrix} C{{H}_{3}}-CH-C{{H}_{3}} \\ \,|\,\,\,\,\,\, \\ \,N{{H}_{2}} \\ \end{matrix}$ $\xrightarrow{HN{{O}_{2}}}$ $\underset{(A)}{\mathop{\begin{matrix} C{{H}_{3}}-CH-C{{H}_{3}} \\ \,|\,\,\,\,\,\, \\ \,OH\, \\ \end{matrix}}}\,$ $\xrightarrow{Oxidation}$ $\underset{(B)}{\mathop{\begin{matrix} O \\ || \\ C{{H}_{3}}-C-C{{H}_{3}} \\ \end{matrix}}}\,$ $\xrightarrow{\begin{smallmatrix} (1)\,C{{H}_{3}}MgBr \\ (2)\,{{H}_{2}}O \end{smallmatrix}}$ $\underset{(C)}{\mathop{\begin{matrix} \begin{matrix} \,\,\,\,OH \\ |\, \\ \end{matrix} \\ C{{H}_{3}}-C-C{{H}_{3}} \\ | \\ \,\,\,\,\,\,\,C{{H}_{3}} \\ \end{matrix}}}\,$

Question

$\begin{array}{*{20}{c}}
{C{H_3} - CH - C{H_3}} \\
{|\,\,\,\,\,} \\
{\,\,N{H_2}}
\end{array}$ ${\xrightarrow{{HN{O_2}}}A}$ ${\xrightarrow{{oxidation}}B}$ ${\xrightarrow[{(ii){\kern 1pt} {H_2}O}]{{(i)C{H_3}MgI}}C}$

$C$ is

A$CH_3CH_2CH_2CH_2OH$
B$\begin{matrix}
C{{H}_{3}}-C{{H}_{2}}-CH-C{{H}_{3}} \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,| \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,OH \\
\end{matrix}$
C$\begin{array}{*{20}{c}}
{C{H_3} - CH - C{H_2} - OH}\\
{\,\,\,\,\,\,\,\,\,\,|}\\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$
D$\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
\,\,\,\,\,\,{C{H_3}}\\
|
\end{array}}\\
{C{H_3} - C - OH}\\
|\\\,\,\,\,\,\,\,
{C{H_3}}
\end{array}$

Difficult

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