$\begin{array}{*{20}{c}}
{{{(C{H_3})}_2}CH - C - N{H_2}\,\xrightarrow[{B{r_2}}]{{NaOH}}A\xrightarrow{{COC{l_2}}}B} \\
{||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$ $B$ is

Q: $\begin{array}{*{20}{c}} {{{(C{H_3})}_2}CH - C - N{H_2}\,\xrightarrow[{B{r_2}}]{{NaOH}}A\xrightarrow{{COC{l_2}}}B} \\ {||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ {O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \end{array}$ $B$ is

a $\begin{array}{*{20}{c}} {\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\ {\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\ {{{(C{H_3})}_2}CH - C - N{H_2}} \end{array}$ $\xrightarrow[{B{r_2}}]{{NaOH}}$ $\mathop {C{H_3}CH - N{H_2}}\limits_{(A)} $ $\xrightarrow{{CoC{l_2}}}$ $\begin{array}{*{20}{c}} {\begin{array}{*{20}{c}} {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\ {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \end{array}} \\ {{{(C{H_3})}_2}CH - NH - C} \\ {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\ {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Cl} \end{array}$ $\xrightarrow[{ - HCl}]{}$ ${(C{H_3})_2}CH - N = C = O$

Question

A$(CH_3)_2CH-N=C=O$
B$\begin{array}{*{20}{c}}
{C{H_3} - CH - C{H_3}} \\
{|\,\,\,} \\
{\,\,\,N{H_2}}
\end{array}$
C$(CH_3)_2CH-NH-COCH_3$
D$CH_3-CH_2-NHCOCH_3$

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