Domain of f(x) = ( x^2 - 1)^ - 1/2 is - Vidyadip

MCQ

Domain of $f(x) = {({x^2} - 1)^{ - 1/2}}$ is

✓
$( - \infty ,\; - 1) \cup (1,\;\infty )$
B
$( - \infty ,\; - 1] \cup (1,\;\infty )$
C
$( - \infty ,\; - 1] \cup [1,\;\infty )$
D
None of these

✓

Answer

Correct option: A.

$( - \infty ,\; - 1) \cup (1,\;\infty )$

a
(a) Here $|x|\,\, > 1,$

therefore $x \in ( - \,\infty ,\, - 1)\, \cup \,(1,\,\,\infty ).$

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