\(y=2 \sin (10 x+300 t)\)
\(y=A \sin (k x+\omega t)\)
\(k=10, \quad \omega=300\)
\(\mu=0.6 \times 10^{-3}\,g / cm\)
\(\mu=\frac{0.6 \times 10^{-3} \times 10^{-3}}{10^{-2}}\,kg / m\)
\(\mu=6 \times 10^{-5}\,kg / m\)
\(K=\frac{\omega}{V}\)
\(V=\frac{\omega}{K}=\frac{30 p}{T p}=30\,m / s\)
\(V=\sqrt{\frac{T}{M}}\)
\(T=V^2 \times M\)
\(T=(30)^2 \times 6 \times 10^{-5}\)
\(=900 \times 6 \times 10^5\)
\(=5400 \times 10^{-5}\)
\(=0.0541\,N\)
(હવામાં ધ્વનિની ઝડપ $= 340\, m/s$)