Question
Draw a right triangle ABC in which $A B=6 cm$, $B C=8 cm$ and $\angle B=90^{\circ}$. Draw $B D$ perpendicular from $B$ on $A C$ and draw a circle passing through the points $B, C$ and $D$. Construct tangents from $A$ to this circle.

Answer

Follow the given steps to construct the figure. Step 1:Draw a line $A B=6 cm$ segment from point B , draw a ray making an angle of $90^{\circ}$ with AB . Now with $B$ as center and radius 8 cm draw an arc cutting the ray at point C. Join AC, to form $\triangle A B C$. Thus, $\triangle A B C$ is created.
Step 2: Bisect BC and name the midpoint of BC as E . So , the center of circle is E .
Step 3: Join points A and E. Bisect AE and name the midpoint of AE is M .
Step 4: With M as centre and ME as radius, draw a circle.
Step 5: Let it intersect given circle at $B$ and $P$.
Step 6: Join AP and AB.
Here, AB and AP are the required tangents to the circle from A
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