Question
Draw a triangle whose sides are of lengths $4\ cm, 5\ cm$ and $7\ cm.$

Answer



Let us assume that given sides are $BC = 7\ cm, AS = 4\ cm$ and $AC = 5\ cm$
Steps of construction:
Step I: Draw a line $BC = 7\ cm.$​​​​​​​
Step II: With centre $B$ and radius $4\ cm$ draw an arc.
Step III: With centre $C$ and radius $5\ cm,$ draw an arc which cuts the previous arc at $A.$​​​​​​​
Step IV: Join $AB$ and $AC.$
Hence, $\triangle\text{ABC}$ is the required triangle in which
$AB = 4\ cm$
$BC = 7\ cm$
$AC = 5\ cm.$

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