Question
Draw an angle equal to $\triangle\text{AOB},$ given in the adjoining figure.
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Answer
Here $\angle\text{AOB}$ is given.
Steps for construction:
$1.$Draw a ray $QP.$
$2.$With $O$ as the centre and any suitable radius, draw an arc cutting $OA$ and $OB$ at $C$ and $E,$ respectively.
$3.$With $Q$ as the centre and the same radius as in step $(2),$ draw an arc cutting $QP$ at $D.$
$4.$With $D$ as the centre and radius equal to $CE,$ cut the arc through $D$ at $F.$
$5.$Draw $QF$ and produce it to point $R.$
$\therefore\ \angle\text{PQR}=\angle\text{AOB}$
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