Question
Draw an angle of measure $147^\circ $ and construct its bisector.

Answer


$i.\ $Draw $\overline {O Q}$ of any length.
$ii.\ $Place the centre of the protractor at $O$ and the zero edge along $\overline {O Q}$ .
$iii.\ $Start with $0$ near $Q.$ Mark a point $P$ at $147^\circ .$
$iv.\ $Join $OP.$ Then, $\angle POQ = 147^\circ .$
$v.\ $With $O$ as centre and using compasses, draw an arc that cuts both rays of $\angle POQ.$ Label the points of intersection as $P'$ and $Q'.$
$vi.\ $With $Q'$ as centre, draw $($in the interior of $\angle POQ)$ an arc whose radius is more than half the length $Q'P'.$
$vii.\ $With the same radius and with $P'$ as centre, draw another arc in the interior of $\angle POQ.$ Let the two arcs intersect at $R.$ Then, $\overline {O R}$ is the bisector of $\angle POQ.$

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