Question
Draw an equilateral triangle one of whose sides is of length $7\ cm$.
✓
Answer
Steps of construction:
Step I: Draw a line segment $AB$ of length $7\ cm$.
Step II: With centre $A$, draw an arc of radius $7\ cm$.
Step III: With centre $B$, draw an arc of radius $7\ cm$ intersecting the previously drawn arc at $C$.
Step IV: Join $AC$ and $BC$ to get the required triangle.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Arrange the following rational number in ascending order:
$\frac{-4}{9}, \frac{5}{-12}, \frac{7}{-18}, \frac{2}{-3}$
→$\frac{-4}{9}, \frac{5}{-12}, \frac{7}{-18}, \frac{2}{-3}$
Simplify the following algebraic expressions by removing grouping symbols.
$-a-[a+\{a+b-2 a-(a-2 b)\}-b]$
→$-a-[a+\{a+b-2 a-(a-2 b)\}-b]$
In the given figure, rays $OA, OB, OC$ and $OD$ are such that $\angle\text{AOB} = 56^\circ,\angle\text{BOC} =100^\circ, \angle\text{COD} = \text{x}^\circ$ and $\angle\text{DOA} = 74^\circ.$ Find the value of $x.$
→If the following pairs represent a pair of equivalent rational numbers, find the values of x:
$\frac{-3}{7}$ and $\frac{x}{4}$
→$\frac{-3}{7}$ and $\frac{x}{4}$
In the following, find of equivalent form of the rational number having a common denominator:
$\frac{2}{3}, \frac{7}{6}$ and $\frac{11}{12}$
→$\frac{2}{3}, \frac{7}{6}$ and $\frac{11}{12}$
$x + 9 = 13$
→Draw $\triangle\text{ABC}$ in which $\angle\text{A}=120^\circ,$ $AB = AC = 3\ cm$. Measure $\angle\text{B}$ and $\angle\text{C}.$
→Write the following as decimals: $23+\frac{2}{10}+\frac{6}{1000}$
→Is it possible to have a triangle with the following sides?
(i) 2 cm, 3 cm, 5 cm
(ii) 3 cm, 6 cm, 7 cm
(iii) 6 cm, 3 cm, 2 cm
(i) 2 cm, 3 cm, 5 cm
(ii) 3 cm, 6 cm, 7 cm
(iii) 6 cm, 3 cm, 2 cm
The area of a circle is $1381m^2$. Find its circumference.
→