Question
Draw the energy bond present in the carbonyl complex ?
✓
Answer
The synergic bond in carbonyl complex is depicted as follows:
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Glucose is an aldohexose monosaccharide. Why does it react with hydrogen cyanide to form cyanohydrin but does not react with sodium hydrogen sulphite?
Two half-reactions of an electrochemical cell are given below:
MnO4- (aq) + 8 H+ (aq) + 5e– → Mn2+ (aq) + 4H2O (l), Eo = +1.51 V,
Sn2+ (aq) → Sn4+ (aq) + 2e–, Eo = +0.15 V.
Construct the redox reaction equation from the two half-reactions and calculate the cell potential from the standard potentials and predict if the reaction is reactant or product favoured.
MnO4- (aq) + 8 H+ (aq) + 5e– → Mn2+ (aq) + 4H2O (l), Eo = +1.51 V,
Sn2+ (aq) → Sn4+ (aq) + 2e–, Eo = +0.15 V.
Construct the redox reaction equation from the two half-reactions and calculate the cell potential from the standard potentials and predict if the reaction is reactant or product favoured.
Why molecularity is applicable only for elementary reactions and order is applicable for elementary as well as complex reactions?
State Henry’s law and mention some important applications?
A first order reaction takes 20 minutes for 25% decomposition. Calculate the time when 75% of the reaction will be completed. (Given : log 2 = 0·3010, log 3 = 0·4771, log 4 = 0·6021)
Why B complex vitamine compounds are essential for us? Describe their important sources.
Write note on physical properties of Ianthanoids.
A reaction is first order in A and second order in B.
- Write the differential rate equation.
- How is the rate affected on increasing the concentration of B three times?
- How is the rate affected when the concentrations of both A and B are doubled?
Match the reactions given in Column I with the names given in Column II.
| Column I | Column II | ||
| (i) |  | (a) | Nucleophilic aromatic substitution |
| (ii) | $\text{CH}_3-\text{CH}==\text{CH}_2+\text{HBr}\xrightarrow{ \ \ \ \ \ }\text{CH}_3-\text{CH}-\text{CH}_3\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ | \ \ \ \ \ \ \ \ \ \ \ \text{Br}$ | (b) | Electrophilic aromatic substitution |
| (iii) |  | (c) | Saytzeff elimination |
| (iv) |  | (d) | Electrophilic addition |
| (v) | $\text{CH}_3\text{CH}_2\text{CH}\text{CH}_3\xrightarrow{\text{alc.KOH}}\text{CH}_3\text{CH}==\text{CH}\text{CH}_3\ \ \ \ \ \ \ |\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{Br}$ | (e) | Nucleophilic substitution (SN1) |