Question
Draw the frequency polygon representing the above data without drawing the histogram.
✓
Answer
We have to draw a frequency polygon without a histogram. Firstly,
we find the class marks of the classes given that is $30-40, 40-50, 50-60, 60-70 .... $
The class mark $=\frac{(30+40)}{2}$
$\Rightarrow\frac{70}{2}=35$ Similarly, we can determine the class marks of the other classes.
So, table for class marks is shown below:
We can draw a frequency polygon by plotting the class marks along the horizontal axis and the frequency along the vertical axis.
Now, plotting all the points $B(35, 3), C(45, 6), D(55, 25), E(65, 65), F(75, 50), G(85, 28), H(95,14)$, also plot the point corresponding to the considering classes $20-30$ and $100-110$ each with frequency 0. Join all these point line segments.
we find the class marks of the classes given that is $30-40, 40-50, 50-60, 60-70 .... $
The class mark $=\frac{(30+40)}{2}$
$\Rightarrow\frac{70}{2}=35$ Similarly, we can determine the class marks of the other classes.
So, table for class marks is shown below:
|
Class interval (km/ h)
|
Class marks
|
Frequency
|
|
$30-40$
$40-50$
$50-60$
$60-70$
$70-80$
$80-90$
$90-100$
|
$35$
$45$
$55$
$65$
$75$
$85$
$95$
|
$3$
$6$
$25$
$65$
$50$
$28$
$14$
|
Now, plotting all the points $B(35, 3), C(45, 6), D(55, 25), E(65, 65), F(75, 50), G(85, 28), H(95,14)$, also plot the point corresponding to the considering classes $20-30$ and $100-110$ each with frequency 0. Join all these point line segments.
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