Question
Draw $\triangle\text{ABC}$ in which $AB = 5.5\ cm. BC = 6\ cm$ and $CA = 7\ cm$. Also, draw perpendicular bisector of side $BC.$
✓
Answer
Steps of construction:
Step I: Draw a line segment $AB$ of length $5.5\ cm.$
Step II: From $B$, cut an arc of radius $6\ cm.$
Step III: With centre $A$, draw an arc of radius $7\ cm$ intersecting the previously drawn arc at $C.$
Step IV: Join $AC$ and $BC$ to obtain the desired triangle.
Step V: With centre $B$ and radius more than half of $BC$, draw two arcs on both sides of $BC$.
Step VI: With centre $C$ and the same radius as in the previous step, draw two arcs intersecting the arcs drawn in the previous step at $X$ and $Y.$
Step VII: Join $XY$ to get the perpendicular bisector of $BC$.
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