Question
Draw $\triangle\text{PQR}$ in which $\angle\text{Q}=80^\circ,$ $\angle\text{R}=55^\circ$ and QR = 4.5cm. Draw the perpendicular bisector of side QR.
✓
Answer
Steps of construction:Step I: Draw a line segment QR = 4.5cm. Step II: Draw $\angle\text{RQX}=80^\circ$ and $\angle\text{QRY}=55^\circ.$ Step III: Let QX and RY intersect at P so that PQR is the required triangle. Step IV: With Q as centre and radius more that 2.25cm, draw arcs on either sides of QR. Step V: With R as centre and radius more than 2.25cm, draw arcs intersecting the previous arcs at M and N. Step VI: Join MN is the required perpendicular bisector of QR.
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