MCQ
During debromination of meso-dibromobutane, the major compound formed is
- A$n-$butane
- B$1-$butane
- Ccis$-2-$butene
- ✓trans$-2-$butene

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$\mathrm{A}(l) \rightarrow 2 \mathrm{B}(\mathrm{g})$
$\Delta \mathrm{U}=2.1\; \mathrm{kcal}, \Delta \mathrm{S}=20\; \mathrm{cal} \mathrm{K}^{-1}$ at $300\; \mathrm{K}$
Hence $\Delta \mathrm{G}$ in $\mathrm{kcal}$ is
