MCQ
During the thermodynamic process shown in figure for an ideal gas
  • A
    $\Delta T=0$
  • B
    $\Delta Q=0$
  • C
    $W < 0$
  • $\Delta U > 0$

Answer

Correct option: D.
$\Delta U > 0$
d
(d)

For a straight $P-V$ graph line $P \propto V$

If pressure increases, volume increases then $T$ also increases $[P V \propto T]$

So $\Delta T \neq 0$

Volume increasing so work is positive, $W > 0$

and temperature also increasing so $\Delta Q > 0$

$\because \Delta Q=\Delta U+\Delta W$

So $\Delta U > 0$

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