MCQ
Each of the points $(-2, 2), (0, 0), (2, 2)$ satisfies the linear equation:
- A$x - y = 0$
- ✓$x + y = 0$
- C$-x + 2y = 0$
- D$x - 2y = 0$
✓
Answer
Correct option: B.
$x + y = 0$
Since given that each of the three points is a solution of the linear equation, all three points have to satisfy the linear equation.
We need to check for each of the four given equations.
Substituting $x = -2$ and $y = 2$ in option $(b),$
We get:
$LHS$
$= x + y$
$= -2 + 2$
$0 = RHS$
$\therefore\ x = -2$ and $y = 2$
Satisfy the given linear equation.
Substituting $x = 0$ and $y = 0$ in option $(b),$
We get:
$LHS$
$= x + y$
$= 0 + 0$
$0 = RHS$
$\therefore\ x = 0$ and $y = 0$
Satisfy the given linear equation.
Substituting $x = -2$ and $y = 2$ in option $(b),$
We get:
$LHS$
$= x + y$
$= 2 - 2$
$0 = RHS$
$\therefore\ x = 2$ and $y = -2$
Satisfy the given linear equation.
So, clearly all the three points satisfy the equation
$x + y = 0.$
We need to check for each of the four given equations.
Substituting $x = -2$ and $y = 2$ in option $(b),$
We get:
$LHS$
$= x + y$
$= -2 + 2$
$0 = RHS$
$\therefore\ x = -2$ and $y = 2$
Satisfy the given linear equation.
Substituting $x = 0$ and $y = 0$ in option $(b),$
We get:
$LHS$
$= x + y$
$= 0 + 0$
$0 = RHS$
$\therefore\ x = 0$ and $y = 0$
Satisfy the given linear equation.
Substituting $x = -2$ and $y = 2$ in option $(b),$
We get:
$LHS$
$= x + y$
$= 2 - 2$
$0 = RHS$
$\therefore\ x = 2$ and $y = -2$
Satisfy the given linear equation.
So, clearly all the three points satisfy the equation
$x + y = 0.$
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