MCQ
Each set $X_r$ contains $5$ elements and each set $Y_r$ contains $4$ elements and
$\bigcup\limits_{r = 1}^{24} {{X_r} = S = \bigcup\limits_{r = 1}^n {{Y_r}} }$ If each element of set $S$ belong to exactly $10$ of the $X_r's$ and to exactly $6$ of $Y_r's$, then $n$ is (where $\bigcup\limits_{r = 1}^{24} {X_r}$ denotes  $X_1 \cup X_2 \cup X_3 \cup ....... \cup X_{24})$
  • $18$
  • B
    $15$
  • C
    $20$
  • D
    $24$

Answer

Correct option: A.
$18$
a
Total elements (with repeation) in

$\bigcup\limits_{r = 1}^{24} {{{\rm{X}}_{\rm{r}}} = 5 \times 24 = 120} $

but each element lie in $10{\rm{ }}{{\rm{x}}_r}$ 's

$\Rightarrow$ Total different elements $=\frac{120}{10}=12$        ....$(i)$

Similarly from $\bigcup\limits_{r = 1}^n {{{\rm{Y}}_{\rm{r}}}} $

we get total different elements $=\frac{4 \mathrm{n}}{6}$        .....$(ii)$

from $(i)$ and $(ii),$   $12=\frac{4 \mathrm{n}}{6}$

$ \Rightarrow \mathrm{n}=18$

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