MCQ
Effective atomic number of $Co(CO)_4$ is $35$, hence it is less stable. It attains stability by
- AOxidation of $Co$
- BReduction of $Co$
- CDimerization
- ✓Both $(B)$ and $(C)$
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$(A)\xrightarrow{{\operatorname{Re}duction}}(B)\xrightarrow{{HN{O_2}}}{C_2}{H_5}OH$