\(VT=\)constant

\(V(p V)=\) constant

\(\therefore p V^{2}=\) constant

In the process \(p V^{x}=\) constant, molar heat capacity is

\(C=\frac{R}{\gamma-1}+\frac{R}{1-x}\)

Here, \(x=2\)

\(\therefore C=\frac{R}{\gamma-1}+\frac{R}{1-2}=\left(\frac{2-\gamma}{\gamma-1}\right) R\)

Now, \(Q=n C \Delta T\)

\(=(1)\left(\frac{2-\gamma}{\gamma-1}\right) R \Delta T\)

\(=\left(\frac{2-\gamma}{\gamma-1}\right) R \Delta T\)