MCQ
Electronic configuration of $Cu(Z = 29)$ is
  • A
    $[Ar]3{d^9}4{s^2}$
  • $[Ar]3{d^{10}}4{s^1}$
  • C
    $[Ar]3{d^5}4{s^2}$
  • D
    $[Ar]3{d^6}4{s^2}$

Answer

Correct option: B.
$[Ar]3{d^{10}}4{s^1}$
b
(b)The expected electronic configuration of $ Cu (29)$  is $[Ar]\;3{d^9}4{s^2}$ but actually it is found to be $[Ar]\;3{d^{10}}4{s^1}$. This is because fully filled $d$  orbitals are more stable than incompletely filled $d-$ orbitals. So there is a migration of one ${e^ - }$, from $4s $ orbital to $3d$  orbital to give a more stable configuration.

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