MCQ
Electronic configuration of ferric ion is
- ✓$[Ar]\,3{d^5}$
- B$[Ar]\,3{d^7}$
- C$[Ar]\,3{d^3}$
- D$[Ar]\,3{d^8}$
$F{e^{3 + }} = [Ar]\,3{d^5}4{s^0}.$
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