MCQ
Electronic configuration of ${H^ - }$ is
- A$1{s^0}$
- B$1{s^1}$
- ✓$1{s^2}$
- D$1{s^1}\,2{s^1}$
✓
Answer
Correct option: C.
$1{s^2}$
c
(c) Electronic configuration of ${H^ - }$ is $1{s^2}$. It has $2 $ electrons in extra nuclear space.
(c) Electronic configuration of ${H^ - }$ is $1{s^2}$. It has $2 $ electrons in extra nuclear space.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
As the temperature increases, the $pH$ of a $KOH$ solution
→A weak acid $HX$ has the dissociation constant $1 \times {10^{ - 5}}\,M$. It forms a salt $NaX$ on reaction with alkali. The degree of hydrolysis of $ 0.1 \,M $ solution of $NaX $ is......$\%$
→In which of the following arrangement the order is not according to the property indicated in bracket
Product $(A)$ is
→Which of the following sets of quantum numbers represent an impossible arrangement
→$n$ $l$ $m$ ${m_s}$
Assuming that $\mathrm{Ba}(\mathrm{OH})_{2}$ is completely ionised in aqueous solution under the given conditions the concentration of $\mathrm{H}_{3} \mathrm{O}^{+}$ions in $0.005 \,\mathrm{M}$ aqueous solution of $\mathrm{Ba}(\mathrm{OH})_{2}$ at $298\, \mathrm{~K}$ is $.....\times 10^{-12}$ $mol$ $\mathrm{L}^{-1}$. (Nearest integer)
→The melting point of $AlF_3$ is $104\,^oC$ and that of $SiF_4$ is $- 77\,^oC$ (it sublimes) because
→${I^ - }(aq.) + MnO_4^ - (aq.)\xrightarrow{{{H^ + }}}X + M{n^{2 + }}(aq.)$
→${I^ - }(aq.) + MnO_4^ - (aq.)\xrightarrow[{weakly\,\,O{H^ - }}]{{Neutral\,\,or}}Y + Mn{O_2}$
$MnO_4^ - (aq.) + M{n^{2 + }}(aq.)\xrightarrow{{ZnS{O_4}}}Z + 4{H^ + }$
Products $X,\,Y$ and $Z$ are respectively :
The $\Delta H$ and $\Delta S$ for a reaction at one atmospheric pressure are $+30.558\, kJ$ and $0.066\,kJ\,{k^{ - 1}}$ respectively. The temperature at which the free energy change will be zero and below of this temperature the nature of reaction would be
→In which of the following the central atom does not use $s{p^3}$ hybrid orbitals in its bonding
→