MCQ
Electrovalent compound's
- AMelting points are low
- BBoiling points are low
- ✓Conduct current in fused state
- DInsoluble in polar solvent
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The product of the above reaction is
$PhC{{O}_{2}}H\xrightarrow[2.\,N{{H}_{3}}]{1.\,PC{{l}_{5}}}A\xrightarrow[2.\,{{H}_{2}}/Ni]{1.\,{{P}_{4}}{{O}_{10}}.heat}B.$ The final product $(B)$ is
$\mathop {Al}\limits_{Metal} \xrightarrow{{HCl(aq.)}}'X' + Gas\,'P'$
$\mathop {Al}\limits_{metal} \xrightarrow[{ + {H_2}O}]{{NaOH\,(aq.)}}'Y' + Gas\,'Q'$


