Question
Eliminate 0 from the following $: x = 5 + 6 \operatorname{cosec} \theta,y = 3 + 8 \cot \theta$

Answer

$ x=5+6 \operatorname{cosec} \theta \text { and } y=3+8 \cot \theta$
$\therefore x-5=6 \operatorname{cosec} \theta \text { and } y-3=8 \cot \theta$
$\therefore \operatorname{cosec} \theta=\frac{x-5}{6} \text { and } \cot \theta=\frac{y-3}{8} $
We know that,
$\operatorname{cosec}^2 \theta-\cot ^2 \theta=1$
$\therefore\left(\frac{x-5}{6}\right)^2-\left(\frac{y-3}{8}\right)^2=1$

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