MCQ
$EN$ of element $A$ is $E_1$ and $IP$ is $E_2$ hence $EA$ will be
- ✓$2E_1 -E_2$
- B$E_1 -E_2$
- C$E_1 -2E_2$
- D$(E_1 + E_2)/2$
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$\Delta U = 2.1\ kcal, \, \Delta S = 20\, cal\, K^{-1}$ at $300\, K$ Hence, $\Delta G$ is ............ $\mathrm{kcal}$