MCQ
Equation $\sqrt {{{(x - 2)}^2} + {y^2}} + \sqrt {{{(x + 2)}^2} + {y^2}} = 4$ represents
- AParabola
- BEllipse
- CCircle
- ✓Pair of straight lines
Squaring both sides, we get $\sqrt {{{(x + 2)}^2} + {y^2}} = x + 2$
Again squaring both sides, we get ${y^2} = 0$, which is the equation of pair of straight lines.
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$I$. $f$ is continuous on the closed interval $[a, b]$
$II.$ $f$ is bounded on the open interval $(a, b)$
$III.$ If $a$ $< a_1< b_1< b$, and $f (a_1)<0< f (b_1)$, then there is $a$ number $c$ such that $a_1 < c < b_1$ and $f (c)=0$
