MCQ
Ether on carbonylation gives
- AAlkanoic acid
- BAlkanone
- ✓Alkyl alkanoate
- DAlkanal
$R - O - R + CO \rightarrow R - CO - O - R$
Thus, it forms the ester Alkyl alkanoate.
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$A{l_{\left( s \right)}}|A{l^{ + 3}}\left( {0.1\,M} \right)||F{e^{ + 2}}\left( {0.001\,M} \right)|Fe\left( s \right)$ If $E_{A{l^{ + 3}}/Al}^o = - 1.66\,V$ and $E_{Fe/F{e^{ + 2}}}^o = + 0.44\,V$

${N_2} + {O_2}$ $\rightleftharpoons$ $2NO - 43,200\,kcal$
