MCQ
Ethers are considered as
- Amonoalkyl derivatives of water
- ✓divalent oxygen atom is attached to two alkyl groups
- Calkyl derivatives of fatty acids
- Dcondensation products of acid and alcohol
✓
Answer
Correct option: B.
divalent oxygen atom is attached to two alkyl groups
divalent oxygen atom is attached to two alkyl groups
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The rate constant for the reaction $2 N_2 O _5(g) \rightarrow 2 N_2 O _4(g)+ O _2(g)$ is $4.98 \times 10^{-4} s^{-1}$. The order of reaction is
→Heat of fusion of ice is $6.02 kJmol -1$ at $0^{\circ} C$. If $100 g$ water is frozen at $0^{\circ} C$, entropy change will be
→
A weak monobasic acid is $2 \%$ dissociated in it's $0.1 M$ solution. What is it's dissociation constant?
→The rate of $S_N 2$ reaction depends on the concentra $\neg$ tion of
→The relationship between $\Delta G^{\circ}$ of a reaction and its equilibrium constant is
→Calculate the amount of solute dissolved in 160 gram solvent that boils at $85^{\circ} \mathrm{C}$, the molar mass of solute is $120 \mathrm{~g} \mathrm{~mol}^{-1}$.
→Diethyl ether is used as a solvent in many organic reactions because it
Find the radius of metal atom in simple cubic unit cell having edge length $334.7 pm$ ?
→Calculate standard potential of a cell having electrode reactions as
$Cd _{( aq )}^{2+}+2 e ^{-} \rightarrow Cd _{( s )} E ^{\circ}=-0.403 V Zn _{( aq )}^{2+}+2 e ^{-} \rightarrow Zn _{( s )} E ^{\circ}=-0.763 V $
→$Cd _{( aq )}^{2+}+2 e ^{-} \rightarrow Cd _{( s )} E ^{\circ}=-0.403 V Zn _{( aq )}^{2+}+2 e ^{-} \rightarrow Zn _{( s )} E ^{\circ}=-0.763 V $