MCQ
Ethyl acetate reacts with $C{H_3}MgBr$ to form
- ASecondary alcohol
- ✓Tertiary alcohol
- CPrimary alcohol and acid
- DAcid
✓
Answer
Correct option: B.
Tertiary alcohol
b
$\underset{Ethyl\,\,acetate}{\mathop{\begin{matrix}
\,O \\
\,|| \\
C{{H}_{3}}C-C-{{C}_{2}}{{H}_{5}} \\
\end{matrix}}}$ $+\,C{{H}_{3}}MgBr\,\to $ $\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,O - MgBr} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}} \\
{C{H_3} - C - O - {C_2}{H_5}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,}
\end{array}$ $\xrightarrow[{ - \,Mg\, < \,\begin{array}{*{20}{c}}
{Br} \\
{OH}
\end{array}}]{{ + \,{H_2}O}}$ $\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,OH} \\
|
\end{array}} \\
{C{H_3} - C - OH} \\
| \\
{\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$ $\xrightarrow{{ - \,{H_2}O}}$ $\begin{array}{*{20}{c}}
O \\
{||} \\
{C{H_3} - C - C{H_3}}
\end{array}$ $\xrightarrow[{C{H_3}MgBr}]{{Excess\,\,of}}$ $\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{C{H_3}\,\,} \\
{|\,\,\,\,\,\,\,\,}
\end{array}} \\
{C{H_3} - C - OMgBr} \\
{\,\,|\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,}
\end{array}$ $\xrightarrow{{{H_2}O}}$ $\mathop {\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{\,\,\,\,\,C{H_3}} \\
|
\end{array}} \\
{C{H_3} - C - OH} \\
{\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,C{H_{3.}}}
\end{array}}\limits_{t\, - \,Butanol} $
$\underset{Ethyl\,\,acetate}{\mathop{\begin{matrix}
\,O \\
\,|| \\
C{{H}_{3}}C-C-{{C}_{2}}{{H}_{5}} \\
\end{matrix}}}$ $+\,C{{H}_{3}}MgBr\,\to $ $\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,O - MgBr} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}} \\
{C{H_3} - C - O - {C_2}{H_5}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,}
\end{array}$ $\xrightarrow[{ - \,Mg\, < \,\begin{array}{*{20}{c}}
{Br} \\
{OH}
\end{array}}]{{ + \,{H_2}O}}$ $\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,OH} \\
|
\end{array}} \\
{C{H_3} - C - OH} \\
| \\
{\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$ $\xrightarrow{{ - \,{H_2}O}}$ $\begin{array}{*{20}{c}}
O \\
{||} \\
{C{H_3} - C - C{H_3}}
\end{array}$ $\xrightarrow[{C{H_3}MgBr}]{{Excess\,\,of}}$ $\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{C{H_3}\,\,} \\
{|\,\,\,\,\,\,\,\,}
\end{array}} \\
{C{H_3} - C - OMgBr} \\
{\,\,|\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,}
\end{array}$ $\xrightarrow{{{H_2}O}}$ $\mathop {\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{\,\,\,\,\,C{H_3}} \\
|
\end{array}} \\
{C{H_3} - C - OH} \\
{\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,C{H_{3.}}}
\end{array}}\limits_{t\, - \,Butanol} $
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The rate of diffusion of $SO _{2},\,CO _{2},\, PCl _{3}$ and $SO _{3}$ are in the following order
→In first transition series, the melting point of $Mn$ is low because
→$0.5\,N$ solution of a salt placed between two platinum electrodes $2.0\,cm$ apart and of area of cross section $4.0\,cm^2$ has a resistance of $25\,ohms$ . Calculate the equivalent conductivity of solution ................. ${\Omega ^{ - 1}}{\rm{c}}{{\rm{m}}^2}{\rm{e}}{{\rm{q}}^{ - 1}}$
→Mixture of volatile components $A$ and $B$ has total vapour pressure (in $torr$ ) $P = 254 \,-\, 119\,X_A$ where $X_A$ is mol fraction of $A$ in mixture. Hence $P_A ^o$ and $P_B^o$ are (in $torr$ )
→Isoelectric point is a
The number of $S-S$ , $S-O-S$ and $O-H$ linkages in a molecule of pyrosulphurous acid are respectively
→For the tetrahedral complex $[ MnBr _{-} 4]^{2-}$, the spin only magnetic moment value is $....$
→[At. no. of $Mn = 25 ]$
Which of the following is used as an acid bath in dyeing cotton and wool?
The Gibbs energy change (in $J$) for the given reaction at $\left[ Cu ^{2+}\right]=\left[ Sn^{2+}\right]=1\, M$ and $298 \,K$ is:
→$Cu ( s )+ Sn ^{2+}( aq ) \rightarrow Cu ^{2+}( aq )+ Sn ( s )$
$\left( E _{ Sn ^{2+} \mid Sn }^{0}=-0.16\, V , E _{ Cu ^{2+} \mid Cu }^{0}=0.34\, V \right.$ Take $F=96500\, C\, mol ^{-1}$ )
In the given reaction $[X]$ will be :
→