MCQ
Ethyl alcohol on heating with conc. ${H_2}S{O_4}$ gives
- A$C{H_3}COO{C_2}{H_5}$
- B${C_2}{H_6}$
- ✓${C_2}{H_4}$
- D${C_2}{H_2}$
✓
Answer
Correct option: C.
${C_2}{H_4}$
c
(c) $C{H_3} - C{H_2} - OH \xrightarrow[H_2SO_4]{Conc.}\mathop {}\limits_{} C{H_2} = C{H_2} + {H_2}O$
(c) $C{H_3} - C{H_2} - OH \xrightarrow[H_2SO_4]{Conc.}\mathop {}\limits_{} C{H_2} = C{H_2} + {H_2}O$
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