Question
Ethyl bromide to ethylamine.
✓
Answer
$\underset{\text { Ethyl bromide }}{ CH _3- CH _2- Br }+\underset{\substack{\text { (alc.) } \\ \text { excess } \\ \text { ammonia }}}{ NH _3} \xrightarrow{\Delta} \underset{\text { Ethylamine }}{ CH _3- CH _2- NH _2+ HBr }$
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