MCQ
Ethyl orthoformate is formed by heating with sodium ethoxide
- ✓$CHC{l_3}$
- B${C_2}{H_5}OH$
- C$HCOOH$
- D$C{H_3}CHO$
✓
Answer
Correct option: A.
$CHC{l_3}$
a
(a)
(a)
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
For an endothermic reaction, $\Delta H$ represents the enthalpy of the reaction in $KJ\,mol^{-1}.$ The minimum amount of activation energy will be
→Four metals $A, B, C, D$ are having $SRP$ value as $-3.05, -1.66, -0.40$ and $0.80 \,V$. Which is strongest reducing Agent ?
→A bromoalkane $'X'$ reacts with magnesium in dry ether to form compound $'Y'$. The reaction of $'Y'$ with methanol followed by hydrolysis yield an alcohol having molecular formula, $C_{4} H_{10} O$. The compound $'X'$ is
→Among $\left[\mathrm{Ni}(\mathrm{CO})_4\right],\left[\mathrm{NiCl}_4\right]^{2-},\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}_2\right] \mathrm{Cl}, \mathrm{Na}_3\left[\mathrm{CoF}_6\right], \mathrm{Na}_2 \mathrm{O}_2$ and $\mathrm{CsO}_2$, the total number of paramagnetic compounds is
→In the electrolysis of water, one Faraday of electrical energy would evolve
$A, B$ and $C$ are three biomolecules. The results of the tests performed on them are given below
→$\begin{array}{|c|c|c|c|}\hline {} &\text { Molisch's Test} & {\text { Barfoed Test}} & {\text { Biuret Test}} \\ \hline \text { A} & { Positive } & {\text { Negative }} & {\text { Negative }} \\ \hline \text { B } & {\text { Positive }} & {\text { Positive }} & {\text { Negative }} \\ \hline \text { C } & {\text { Negative }} & {\text { Negative }} & {\text { Positive }} \\ \hline\end{array}$
$A, B$ and $C$ are respectively
A radioactive element has a half life of $200\, days.$ The percentage of original activity remaining after $83\, days$ is $....$ (Nearest integer)
→(Given : antilog $0.125=1.333$, antilog $0.693=$ 4.93)
Deduce structure of $(A)$.
→$(A)\,{{C}_{8}}{{H}_{10}}\xrightarrow{KMn{{O}_{4}}}(B){{C}_{8}}{{H}_{6}}{{O}_{4}}\xrightarrow[Fe]{B{{r}_{2}}}{{C}_{8}}{{H}_{5}}Br{{O}_{4}}(C)$ (one-product only)
The main reduction product of the following compound with $NaBH_4$ in methanol is
→Product $(A)$ of the above reaction is
→