Question
Ethylamine to ethyl alcohol.
✓
Answer
$\begin{array}{ll} \underset{\text{Ethylamine }}{C _2 H _5-} NH _2+ HO - N = O \quad \xrightarrow{ NaNO _2+\text { dil. } HCl } &\underset{\text{Ethyl alcohol}}{ C _2 H _5 OH} + H _2 O + N _2 \uparrow \\ \text { } \quad \text { }\end{array}$
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