MCQ
Ethylene chloride and ethylidene chloride are isomers. Identify the correct statements.
  • A
    Both the compounds form same product on treatment with alcoholic KOH.
  • B
    Both the compounds form same product on treatment with aq.NaOH.
  • C
    Both the compounds form same product on reduction.
  • D
    Both the compounds are optically active.

Answer

  1. Both the compounds form same product on treatment with alcoholic KOH.
  1. Both the compounds form same product on reduction.

Explanation:

$\text{H}_3\text{C}-\text{CHCl}_2$ (ethylidene choride) and $\text{H}_2\text{C}-\text{CH}_2\\ \ \ \ \ \ \ | \ \ \ \ \ \ |\ \ \ \ \\ \ \ \ \ \ \text{Cl} \ \ \ \text{Cl}$ (ethylene dichloride) are isomers.

  1. They give ethyne on treatment with alcoholic KOH.

$\text{CH}_3\text{CHCl}_2\xrightarrow[\text{KOH}]{ \ \ \ \text{alc.} \ \ \ \ }\text{CH}\equiv\text{CH}+2\text{KCl}+2\text{H}_2\text{O}$

$\text{Cl}-\text{CH}_2-\text{CH}_2-\text{Cl}\xrightarrow{ \ \ \text{alc.KOH} \ \ }\text{CH}\equiv\text{CH}+2\text{KCl}+\text{H}_2\text{O}$

  1. On reduction with Zn dust in alcohol they give ethylene.

$\text{CH}_3\text{CHCl}_2\xrightarrow{ \ \ \text{CH}_3\text{OH} \ \ \ }\text{CH}_2=\text{CH}$

$\text{Cl}-\text{CH}_2-\text{CH}_2-\text{Cl}+\text{Zn}\xrightarrow{\text{CH}_3\text{OH} \ \ }\text{CH}_2=\text{CH}_2$

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