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STD 11 - 9. Hydricarbon — NEET STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceNEETSTD 11 - 9. Hydricarbon4 Marks
MCQ
Ethylene is prepared by the dehydration of
  • ✓
    Ethyl alcohol
  • B
    Methyl alcohol
  • C
    Acetic acid
  • D
    Oxalic acid
✓

Answer

Correct option: A.
Ethyl alcohol
a
(a) $C{{H}_{3}}-C{{H}_{2}}-OH\underset{\text{Dehydration}}{\mathop{\xrightarrow{\text{Conc}\text{. }{{H}_{2}}S{{O}_{4}}}}}\,C{{H}_{2}}=C{{H}_{2}}+{{H}_{2}}O$

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