- AChloroethane
- ✓Ethylene dibromide
- CCyclohexane
- D$1-$ bromo propane
$\mathop {{H_2}C = C{H_2}}\limits_{{\text{Ethylene}}} \; + \mathop {B{r_2}}\limits_{{\text{Bromine}}} \to $ $\mathop {\begin{array}{*{20}{c}}
{{H_2}C - C{H_2}} \\
{|\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,Br\,\,\,\,\,Br}
\end{array}}\limits_{Ethylene\,\,dibromide} $
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Reason : Covalency of oxygen is two.
Reason : $\overset{\centerdot \,\,\centerdot }{\mathop{N}}\,{{H}_{2}}$ is more electron donating than $\overset{\centerdot \,\centerdot \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}{\mathop{O{{C}_{2}}{{H}_{5}}}}\,$
$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,OH} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,} \\
{C{H_3} - CH = CH - C{H_2} - CH - C{H_3}}
\end{array}$ $\longrightarrow $ $C{H_3} - CH = CH - C{H_2}C{O_2}H$
